Distance from Fuquay-Varina to Aleksandrovac
The shortest distance (air line) between Fuquay-Varina and Aleksandrovac is 5,014.00 mi (8,069.25 km).
How far is Fuquay-Varina from Aleksandrovac
Fuquay-Varina is located in North Carolina, United States within 35° 35' 43.08" N -79° 13' 19.92" W (35.5953, -78.7778) coordinates. The local time in Fuquay-Varina is 21:32 (28.02.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 03:32 (01.03.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,014.00 miles which is equal to 8,069.25 km.
Fuquay-Varina, North Carolina, United States
Related Distances from Fuquay-Varina
Aleksandrovac, Rasinska oblast, Serbia