Distance from Fuquay-Varina to Diepenbeek
The shortest distance (air line) between Fuquay-Varina and Diepenbeek is 4,129.09 mi (6,645.12 km).
How far is Fuquay-Varina from Diepenbeek
Fuquay-Varina is located in North Carolina, United States within 35° 35' 43.08" N -79° 13' 19.92" W (35.5953, -78.7778) coordinates. The local time in Fuquay-Varina is 21:03 (01.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 03:03 (02.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,129.09 miles which is equal to 6,645.12 km.
Fuquay-Varina, North Carolina, United States
Related Distances from Fuquay-Varina
Diepenbeek, Arr. Hasselt, Belgium