Distance from Fuquay-Varina to Sendenhorst
The shortest distance (air line) between Fuquay-Varina and Sendenhorst is 4,202.81 mi (6,763.76 km).
How far is Fuquay-Varina from Sendenhorst
Fuquay-Varina is located in North Carolina, United States within 35° 35' 43.08" N -79° 13' 19.92" W (35.5953, -78.7778) coordinates. The local time in Fuquay-Varina is 00:07 (09.02.2025)
Sendenhorst is located in Warendorf, Germany within 51° 50' 38.04" N 7° 49' 40.08" E (51.8439, 7.8278) coordinates. The local time in Sendenhorst is 06:07 (09.02.2025)
The calculated flying distance from Sendenhorst to Sendenhorst is 4,202.81 miles which is equal to 6,763.76 km.
Fuquay-Varina, North Carolina, United States
Related Distances from Fuquay-Varina
Sendenhorst, Warendorf, Germany