Distance from Fuquay-Varina to Sveti Ivan Zelina
The shortest distance (air line) between Fuquay-Varina and Sveti Ivan Zelina is 4,722.51 mi (7,600.15 km).
How far is Fuquay-Varina from Sveti Ivan Zelina
Fuquay-Varina is located in North Carolina, United States within 35° 35' 43.08" N -79° 13' 19.92" W (35.5953, -78.7778) coordinates. The local time in Fuquay-Varina is 20:02 (02.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 02:02 (03.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,722.51 miles which is equal to 7,600.15 km.
Fuquay-Varina, North Carolina, United States
Related Distances from Fuquay-Varina
Sveti Ivan Zelina, Zagrebačka županija, Croatia