Distance from Gainesville to Begijnendijk
The shortest distance (air line) between Gainesville and Begijnendijk is 4,536.15 mi (7,300.22 km).
How far is Gainesville from Begijnendijk
Gainesville is located in Florida, United States within 29° 40' 49.44" N -83° 39' 14.76" W (29.6804, -82.3459) coordinates. The local time in Gainesville is 05:46 (04.03.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 11:46 (04.03.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,536.15 miles which is equal to 7,300.22 km.
Gainesville, Florida, United States
Related Distances from Gainesville
Begijnendijk, Arr. Leuven, Belgium