Distance from Gainesville to Celakovice
The shortest distance (air line) between Gainesville and Celakovice is 4,964.58 mi (7,989.72 km).
How far is Gainesville from Celakovice
Gainesville is located in Florida, United States within 29° 40' 49.44" N -83° 39' 14.76" W (29.6804, -82.3459) coordinates. The local time in Gainesville is 02:52 (08.05.2025)
Celakovice is located in Středočeský kraj, Czechia within 50° 9' 38.16" N 14° 45' 0" E (50.1606, 14.7500) coordinates. The local time in Celakovice is 08:52 (08.05.2025)
The calculated flying distance from Celakovice to Celakovice is 4,964.58 miles which is equal to 7,989.72 km.
Gainesville, Florida, United States
Related Distances from Gainesville
Celakovice, Středočeský kraj, Czechia