Distance from Gainesville to Scherpenheuvel
The shortest distance (air line) between Gainesville and Scherpenheuvel is 4,544.09 mi (7,313.01 km).
How far is Gainesville from Scherpenheuvel
Gainesville is located in Florida, United States within 29° 40' 49.44" N -83° 39' 14.76" W (29.6804, -82.3459) coordinates. The local time in Gainesville is 10:18 (02.05.2025)
Scherpenheuvel is located in Arr. Leuven, Belgium within 51° 0' 37.08" N 4° 58' 22.08" E (51.0103, 4.9728) coordinates. The local time in Scherpenheuvel is 16:18 (02.05.2025)
The calculated flying distance from Scherpenheuvel to Scherpenheuvel is 4,544.09 miles which is equal to 7,313.01 km.
Gainesville, Florida, United States
Related Distances from Gainesville
Scherpenheuvel, Arr. Leuven, Belgium