Distance from Gainesville to Sint-Andries
The shortest distance (air line) between Gainesville and Sint-Andries is 4,466.06 mi (7,187.43 km).
How far is Gainesville from Sint-Andries
Gainesville is located in Florida, United States within 29° 40' 49.44" N -83° 39' 14.76" W (29.6804, -82.3459) coordinates. The local time in Gainesville is 00:00 (30.04.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 06:00 (30.04.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,466.06 miles which is equal to 7,187.43 km.
Gainesville, Florida, United States
Related Distances from Gainesville
Sint-Andries, Arr. Brugge, Belgium