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      Distance from Gainesville to Sint-Pieters-Leeuw

      The shortest distance (air line) between Gainesville and Sint-Pieters-Leeuw is 4,518.85 mi (7,272.38 km).

      How far is Gainesville from Sint-Pieters-Leeuw

      Gainesville is located in Florida, United States within 29° 40' 49.44" N -83° 39' 14.76" W (29.6804, -82.3459) coordinates. The local time in Gainesville is 02:20 (05.06.2025)

      Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 08:20 (05.06.2025)

      The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 4,518.85 miles which is equal to 7,272.38 km.

      Gainesville, Florida, United States

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      Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Pieters-Leeuw