Distance from Greenville to Ciempozuelos
The shortest distance (air line) between Greenville and Ciempozuelos is 4,187.49 mi (6,739.12 km).
How far is Greenville from Ciempozuelos
Greenville is located in South Carolina, United States within 34° 50' 7.44" N -83° 38' 7.44" W (34.8354, -82.3646) coordinates. The local time in Greenville is 02:53 (10.03.2025)
Ciempozuelos is located in Madrid, Spain within 40° 9' 33.12" N -4° 22' 54.12" W (40.1592, -3.6183) coordinates. The local time in Ciempozuelos is 08:53 (10.03.2025)
The calculated flying distance from Ciempozuelos to Ciempozuelos is 4,187.49 miles which is equal to 6,739.12 km.
Greenville, South Carolina, United States