Distance from Greenville to Lyaskovets
The shortest distance (air line) between Greenville and Lyaskovets is 5,403.92 mi (8,696.76 km).
How far is Greenville from Lyaskovets
Greenville is located in South Carolina, United States within 34° 50' 7.44" N -83° 38' 7.44" W (34.8354, -82.3646) coordinates. The local time in Greenville is 21:26 (22.01.2025)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 04:26 (23.01.2025)
The calculated flying distance from Lyaskovets to Lyaskovets is 5,403.92 miles which is equal to 8,696.76 km.
Greenville, South Carolina, United States
Related Distances from Greenville
Lyaskovets, Veliko Tarnovo, Bulgaria