Distance from Griffin to Begijnendijk
The shortest distance (air line) between Griffin and Begijnendijk is 4,437.88 mi (7,142.08 km).
How far is Griffin from Begijnendijk
Griffin is located in Georgia, United States within 33° 14' 30.48" N -85° 43' 30.72" W (33.2418, -84.2748) coordinates. The local time in Griffin is 19:33 (01.02.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 01:33 (02.02.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,437.88 miles which is equal to 7,142.08 km.
Griffin, Georgia, United States
Related Distances from Griffin
Begijnendijk, Arr. Leuven, Belgium