Distance from Griffith to Diepenbeek
The shortest distance (air line) between Griffith and Diepenbeek is 4,185.91 mi (6,736.57 km).
How far is Griffith from Diepenbeek
Griffith is located in Indiana, United States within 41° 31' 39.72" N -88° 34' 33.96" W (41.5277, -87.4239) coordinates. The local time in Griffith is 13:10 (08.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 20:10 (08.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,185.91 miles which is equal to 6,736.57 km.
Griffith, Indiana, United States
Related Distances from Griffith
Diepenbeek, Arr. Hasselt, Belgium