Distance from Griffith to Mercato San Severino
The shortest distance (air line) between Griffith and Mercato San Severino is 4,956.63 mi (7,976.92 km).
How far is Griffith from Mercato San Severino
Griffith is located in Indiana, United States within 41° 31' 39.72" N -88° 34' 33.96" W (41.5277, -87.4239) coordinates. The local time in Griffith is 04:41 (23.02.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 11:41 (23.02.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 4,956.63 miles which is equal to 7,976.92 km.
Griffith, Indiana, United States
Related Distances from Griffith
Mercato San Severino, Salerno, Italy