Distance from Haaksbergen to Aleksandrow Kujawski
The shortest distance (air line) between Haaksbergen and Aleksandrow Kujawski is 504.12 mi (811.31 km).
How far is Haaksbergen from Aleksandrow Kujawski
Haaksbergen is located in Twente, Netherlands within 52° 8' 60" N 6° 45' 0" E (52.1500, 6.7500) coordinates. The local time in Haaksbergen is 22:58 (03.03.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 22:58 (03.03.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 504.12 miles which is equal to 811.31 km.
Haaksbergen, Twente, Netherlands
Related Distances from Haaksbergen
Aleksandrow Kujawski, Włocławski, Poland