Distance from Haaksbergen to Vetraz-Monthoux
The shortest distance (air line) between Haaksbergen and Vetraz-Monthoux is 413.49 mi (665.45 km).
How far is Haaksbergen from Vetraz-Monthoux
Haaksbergen is located in Twente, Netherlands within 52° 8' 60" N 6° 45' 0" E (52.1500, 6.7500) coordinates. The local time in Haaksbergen is 09:58 (31.01.2025)
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 09:58 (31.01.2025)
The calculated flying distance from Vetraz-Monthoux to Vetraz-Monthoux is 413.49 miles which is equal to 665.45 km.
Haaksbergen, Twente, Netherlands
Related Distances from Haaksbergen
Vetraz-Monthoux, Haute-Savoie, France