Distance from Hackensack to Aleksandrow Lodzki
The shortest distance (air line) between Hackensack and Aleksandrow Lodzki is 4,203.64 mi (6,765.11 km).
How far is Hackensack from Aleksandrow Lodzki
Hackensack is located in New Jersey, United States within 40° 53' 20.76" N -75° 57' 13.68" W (40.8891, -74.0462) coordinates. The local time in Hackensack is 15:10 (17.05.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 21:10 (17.05.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,203.64 miles which is equal to 6,765.11 km.
Hackensack, New Jersey, United States
Related Distances from Hackensack
Aleksandrow Lodzki, Łódzki, Poland