Distance from Hackettstown to Diepenbeek
The shortest distance (air line) between Hackettstown and Diepenbeek is 3,727.45 mi (5,998.75 km).
How far is Hackettstown from Diepenbeek
Hackettstown is located in New Jersey, United States within 40° 51' 14.4" N -75° 10' 27.48" W (40.8540, -74.8257) coordinates. The local time in Hackettstown is 00:17 (13.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 06:17 (13.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 3,727.45 miles which is equal to 5,998.75 km.
Hackettstown, New Jersey, United States
Related Distances from Hackettstown
Diepenbeek, Arr. Hasselt, Belgium