Distance from Hampton Bays to Steenokkerzeel
The shortest distance (air line) between Hampton Bays and Steenokkerzeel is 3,596.56 mi (5,788.10 km).
How far is Hampton Bays from Steenokkerzeel
Hampton Bays is located in New York, United States within 40° 52' 10.2" N -73° 28' 39" W (40.8695, -72.5225) coordinates. The local time in Hampton Bays is 09:23 (22.02.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 15:23 (22.02.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 3,596.56 miles which is equal to 5,788.10 km.
Hampton Bays, New York, United States
Related Distances from Hampton Bays
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium