Distance from Harker Heights to Aleksandrovac
The shortest distance (air line) between Harker Heights and Aleksandrovac is 5,995.66 mi (9,649.08 km).
How far is Harker Heights from Aleksandrovac
Harker Heights is located in Texas, United States within 31° 3' 25.92" N -98° 21' 19.44" W (31.0572, -97.6446) coordinates. The local time in Harker Heights is 02:39 (24.05.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 09:39 (24.05.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,995.66 miles which is equal to 9,649.08 km.
Harker Heights, Texas, United States
Related Distances from Harker Heights
Aleksandrovac, Rasinska oblast, Serbia