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      Distance from Harker Heights to Blunsdon Saint Andrew

      The shortest distance (air line) between Harker Heights and Blunsdon Saint Andrew is 4,802.47 mi (7,728.83 km).

      How far is Harker Heights from Blunsdon Saint Andrew

      Harker Heights is located in Texas, United States within 31° 3' 25.92" N -98° 21' 19.44" W (31.0572, -97.6446) coordinates. The local time in Harker Heights is 12:08 (16.06.2025)

      Blunsdon Saint Andrew is located in Swindon, United Kingdom within 51° 36' 36" N -2° 12' 36" W (51.6100, -1.7900) coordinates. The local time in Blunsdon Saint Andrew is 18:08 (16.06.2025)

      The calculated flying distance from Blunsdon Saint Andrew to Blunsdon Saint Andrew is 4,802.47 miles which is equal to 7,728.83 km.

      Harker Heights, Texas, United States

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      Harker Heights to Miami (Florida)1,118.78 mi (1,800.50 km)
      Harker Heights to Detroit (Michigan)1,119.89 mi (1,802.29 km)
      Harker Heights to San Diego (California)1,146.89 mi (1,845.74 km)
      Harker Heights to Riverside (California)1,166.12 mi (1,876.69 km)
      Harker Heights to Los Angeles (California)1,224.81 mi (1,971.14 km)
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      Harker Heights to Philadelphia (Pennsylvania)1,403.28 mi (2,258.36 km)
      Harker Heights to Brooklyn (New York)1,476.76 mi (2,376.62 km)
      Harker Heights to New York (New York)1,478.99 mi (2,380.20 km)
      Harker Heights to San Francisco (California)1,482.34 mi (2,385.60 km)
      Harker Heights to Queens (New York)1,486.54 mi (2,392.36 km)
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      Harker Heights to Portland (Oregon)1,673.29 mi (2,692.90 km)
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      Blunsdon Saint Andrew, Swindon, United Kingdom

      Related Distances to Blunsdon Saint Andrew