Distance from Harker Heights to East Patchogue
The shortest distance (air line) between Harker Heights and East Patchogue is 1,527.44 mi (2,458.18 km).
How far is Harker Heights from East Patchogue
Harker Heights is located in Texas, United States within 31° 3' 25.92" N -98° 21' 19.44" W (31.0572, -97.6446) coordinates. The local time in Harker Heights is 14:30 (22.06.2025)
East Patchogue is located in New York, United States within 40° 46' 13.44" N -73° 1' 5.88" W (40.7704, -72.9817) coordinates. The local time in East Patchogue is 15:30 (22.06.2025)
The calculated flying distance from East Patchogue to East Patchogue is 1,527.44 miles which is equal to 2,458.18 km.
Harker Heights, Texas, United States
Related Distances from Harker Heights
East Patchogue, New York, United States