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      Distance from Harker Heights to Villanueva de la Serena

      The shortest distance (air line) between Harker Heights and Villanueva de la Serena is 4,999.78 mi (8,046.37 km).

      How far is Harker Heights from Villanueva de la Serena

      Harker Heights is located in Texas, United States within 31° 3' 25.92" N -98° 21' 19.44" W (31.0572, -97.6446) coordinates. The local time in Harker Heights is 05:38 (03.01.2026)

      Villanueva de la Serena is located in Badajoz, Spain within 38° 58' 0.12" N -6° 12' 0" W (38.9667, -5.8000) coordinates. The local time in Villanueva de la Serena is 12:38 (03.01.2026)

      The calculated flying distance from Villanueva de la Serena to Villanueva de la Serena is 4,999.78 miles which is equal to 8,046.37 km.

      Harker Heights, Texas, United States

      Related Distances from Harker Heights

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      Harker Heights to Miami (Florida)1,118.78 mi (1,800.50 km)
      Harker Heights to Detroit (Michigan)1,119.89 mi (1,802.29 km)
      Harker Heights to San Diego (California)1,146.89 mi (1,845.74 km)
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      Harker Heights to Philadelphia (Pennsylvania)1,403.28 mi (2,258.36 km)
      Harker Heights to Brooklyn (New York)1,476.76 mi (2,376.62 km)
      Harker Heights to New York (New York)1,478.99 mi (2,380.20 km)
      Harker Heights to San Francisco (California)1,482.34 mi (2,385.60 km)
      Harker Heights to Queens (New York)1,486.54 mi (2,392.36 km)
      Harker Heights to Boston (Massachusetts)1,654.77 mi (2,663.09 km)
      Harker Heights to Portland (Oregon)1,673.29 mi (2,692.90 km)
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      Villanueva de la Serena, Badajoz, Spain

      Related Distances to Villanueva de la Serena