Distance from Harrisonburg to Sveti Ivan Zelina
The shortest distance (air line) between Harrisonburg and Sveti Ivan Zelina is 4,596.62 mi (7,397.54 km).
How far is Harrisonburg from Sveti Ivan Zelina
Harrisonburg is located in Virginia, United States within 38° 26' 10.32" N -79° 7' 35.4" W (38.4362, -78.8735) coordinates. The local time in Harrisonburg is 04:41 (23.01.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 10:41 (23.01.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,596.62 miles which is equal to 7,397.54 km.
Harrisonburg, Virginia, United States
Related Distances from Harrisonburg
Sveti Ivan Zelina, Zagrebačka županija, Croatia