Distance from Hartsville to Aleksandrovac
The shortest distance (air line) between Hartsville and Aleksandrovac is 5,278.51 mi (8,494.94 km).
How far is Hartsville from Aleksandrovac
Hartsville is located in Tennessee, United States within 36° 23' 31.56" N -87° 50' 35.52" W (36.3921, -86.1568) coordinates. The local time in Hartsville is 17:56 (09.03.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 00:56 (10.03.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,278.51 miles which is equal to 8,494.94 km.
Hartsville, Tennessee, United States
Related Distances from Hartsville
Aleksandrovac, Rasinska oblast, Serbia