Distance from Hasbrouck Heights to Aleksandrow Lodzki
The shortest distance (air line) between Hasbrouck Heights and Aleksandrow Lodzki is 4,206.01 mi (6,768.91 km).
How far is Hasbrouck Heights from Aleksandrow Lodzki
Hasbrouck Heights is located in New Jersey, United States within 40° 51' 42.48" N -75° 55' 33.24" W (40.8618, -74.0741) coordinates. The local time in Hasbrouck Heights is 15:15 (18.05.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 21:15 (18.05.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,206.01 miles which is equal to 6,768.91 km.
Hasbrouck Heights, New Jersey, United States
Related Distances from Hasbrouck Heights
Aleksandrow Lodzki, Łódzki, Poland