Distance from Hayesville to Scherpenheuvel
The shortest distance (air line) between Hayesville and Scherpenheuvel is 5,112.53 mi (8,227.82 km).
How far is Hayesville from Scherpenheuvel
Hayesville is located in Oregon, United States within 44° 58' 45.48" N -123° 1' 34.32" W (44.9793, -122.9738) coordinates. The local time in Hayesville is 03:15 (05.04.2025)
Scherpenheuvel is located in Arr. Leuven, Belgium within 51° 0' 37.08" N 4° 58' 22.08" E (51.0103, 4.9728) coordinates. The local time in Scherpenheuvel is 12:15 (05.04.2025)
The calculated flying distance from Scherpenheuvel to Scherpenheuvel is 5,112.53 miles which is equal to 8,227.82 km.
Hayesville, Oregon, United States
Related Distances from Hayesville
Scherpenheuvel, Arr. Leuven, Belgium