Distance from Hazebrouck to Aleksandrow Kujawski
The shortest distance (air line) between Hazebrouck and Aleksandrow Kujawski is 704.44 mi (1,133.69 km).
How far is Hazebrouck from Aleksandrow Kujawski
Hazebrouck is located in Nord, France within 50° 43' 30" N 2° 32' 21.12" E (50.7250, 2.5392) coordinates. The local time in Hazebrouck is 11:05 (19.05.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 11:05 (19.05.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 704.44 miles which is equal to 1,133.69 km.
Related Distances from Hazebrouck
Aleksandrow Kujawski, Włocławski, Poland