Distance from Hickory to Aleksandrow Lodzki
The shortest distance (air line) between Hickory and Aleksandrow Lodzki is 4,732.30 mi (7,615.90 km).
How far is Hickory from Aleksandrow Lodzki
Hickory is located in North Carolina, United States within 35° 44' 27.6" N -82° 40' 39.72" W (35.7410, -81.3223) coordinates. The local time in Hickory is 00:31 (13.03.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 06:31 (13.03.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,732.30 miles which is equal to 7,615.90 km.
Hickory, North Carolina, United States
Related Distances from Hickory
Aleksandrow Lodzki, Łódzki, Poland