Distance from Hickory to Sveti Ivan Zelina
The shortest distance (air line) between Hickory and Sveti Ivan Zelina is 4,821.40 mi (7,759.29 km).
How far is Hickory from Sveti Ivan Zelina
Hickory is located in North Carolina, United States within 35° 44' 27.6" N -82° 40' 39.72" W (35.7410, -81.3223) coordinates. The local time in Hickory is 03:33 (11.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 09:33 (11.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,821.40 miles which is equal to 7,759.29 km.
Hickory, North Carolina, United States
Related Distances from Hickory
Sveti Ivan Zelina, Zagrebačka županija, Croatia