Distance from Hinesville to Bad Sassendorf
The shortest distance (air line) between Hinesville and Bad Sassendorf is 4,523.46 mi (7,279.81 km).
How far is Hinesville from Bad Sassendorf
Hinesville is located in Georgia, United States within 31° 49' 29.28" N -82° 23' 10.68" W (31.8248, -81.6137) coordinates. The local time in Hinesville is 18:18 (11.02.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 00:18 (12.02.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,523.46 miles which is equal to 7,279.81 km.
Hinesville, Georgia, United States
Related Distances from Hinesville
Bad Sassendorf, Soest, Germany