Distance from Hinesville to Sveti Ivan Zelina
The shortest distance (air line) between Hinesville and Sveti Ivan Zelina is 5,019.14 mi (8,077.53 km).
How far is Hinesville from Sveti Ivan Zelina
Hinesville is located in Georgia, United States within 31° 49' 29.28" N -82° 23' 10.68" W (31.8248, -81.6137) coordinates. The local time in Hinesville is 00:20 (10.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 06:20 (10.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,019.14 miles which is equal to 8,077.53 km.
Hinesville, Georgia, United States
Related Distances from Hinesville
Sveti Ivan Zelina, Zagrebačka županija, Croatia