Distance from Holtsville to Aleksandrow Lodzki
The shortest distance (air line) between Holtsville and Aleksandrow Lodzki is 4,170.29 mi (6,711.43 km).
How far is Holtsville from Aleksandrow Lodzki
Holtsville is located in New York, United States within 40° 48' 44.64" N -74° 57' 19.08" W (40.8124, -73.0447) coordinates. The local time in Holtsville is 17:02 (02.03.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 23:02 (02.03.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,170.29 miles which is equal to 6,711.43 km.
Holtsville, New York, United States
Related Distances from Holtsville
Aleksandrow Lodzki, Łódzki, Poland