Distance from Holtsville to Janow Lubelski
The shortest distance (air line) between Holtsville and Janow Lubelski is 4,324.87 mi (6,960.21 km).
How far is Holtsville from Janow Lubelski
Holtsville is located in New York, United States within 40° 48' 44.64" N -74° 57' 19.08" W (40.8124, -73.0447) coordinates. The local time in Holtsville is 13:35 (03.03.2025)
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 19:35 (03.03.2025)
The calculated flying distance from Janow Lubelski to Janow Lubelski is 4,324.87 miles which is equal to 6,960.21 km.
Holtsville, New York, United States
Related Distances from Holtsville
Janow Lubelski, Puławski, Poland