Distance from Hopkins to Dimitrovgrad
The shortest distance (air line) between Hopkins and Dimitrovgrad is 5,204.57 mi (8,375.95 km).
How far is Hopkins from Dimitrovgrad
Hopkins is located in Minnesota, United States within 44° 55' 33.24" N -94° 35' 39.84" W (44.9259, -93.4056) coordinates. The local time in Hopkins is 02:47 (09.02.2025)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 09:47 (09.02.2025)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 5,204.57 miles which is equal to 8,375.95 km.
Hopkins, Minnesota, United States
Related Distances from Hopkins
Dimitrovgrad, Pirotska oblast, Serbia