Distance from Hopkinsville to Diepenbeek
The shortest distance (air line) between Hopkinsville and Diepenbeek is 4,415.49 mi (7,106.05 km).
How far is Hopkinsville from Diepenbeek
Hopkinsville is located in Kentucky, United States within 36° 50' 17.16" N -88° 31' 21" W (36.8381, -87.4775) coordinates. The local time in Hopkinsville is 17:02 (08.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 00:02 (09.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,415.49 miles which is equal to 7,106.05 km.
Hopkinsville, Kentucky, United States
Related Distances from Hopkinsville
Diepenbeek, Arr. Hasselt, Belgium