Distance from Hopkinsville to Sajoszentpeter
The shortest distance (air line) between Hopkinsville and Sajoszentpeter is 5,092.66 mi (8,195.84 km).
How far is Hopkinsville from Sajoszentpeter
Hopkinsville is located in Kentucky, United States within 36° 50' 17.16" N -88° 31' 21" W (36.8381, -87.4775) coordinates. The local time in Hopkinsville is 12:10 (04.03.2025)
Sajoszentpeter is located in Borsod-Abaúj-Zemplén, Hungary within 48° 13' 0.84" N 20° 43' 5.88" E (48.2169, 20.7183) coordinates. The local time in Sajoszentpeter is 19:10 (04.03.2025)
The calculated flying distance from Sajoszentpeter to Sajoszentpeter is 5,092.66 miles which is equal to 8,195.84 km.
Hopkinsville, Kentucky, United States
Related Distances from Hopkinsville
Sajoszentpeter, Borsod-Abaúj-Zemplén, Hungary