Distance from Huntington to Sansepolcro
The shortest distance (air line) between Huntington and Sansepolcro is 934.16 mi (1,503.39 km).
How far is Huntington from Sansepolcro
Huntington is located in York, United Kingdom within 53° 59' 33.36" N -2° 57' 25.2" W (53.9926, -1.0430) coordinates. The local time in Huntington is 19:28 (22.05.2025)
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 20:28 (22.05.2025)
The calculated flying distance from Sansepolcro to Sansepolcro is 934.16 miles which is equal to 1,503.39 km.
Huntington, York, United Kingdom