Distance from Huntington Park to Steenokkerzeel
The shortest distance (air line) between Huntington Park and Steenokkerzeel is 5,617.37 mi (9,040.28 km).
How far is Huntington Park from Steenokkerzeel
Huntington Park is located in California, United States within 33° 58' 48" N -119° 46' 59.88" W (33.9800, -118.2167) coordinates. The local time in Huntington Park is 05:23 (23.01.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 14:23 (23.01.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 5,617.37 miles which is equal to 9,040.28 km.
Huntington Park, California, United States
Related Distances from Huntington Park
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium