Distance from Hyattsville to Drobeta-Turnu Severin
The shortest distance (air line) between Hyattsville and Drobeta-Turnu Severin is 4,805.20 mi (7,733.22 km).
How far is Hyattsville from Drobeta-Turnu Severin
Hyattsville is located in Maryland, United States within 38° 57' 40.68" N -77° 2' 42.72" W (38.9613, -76.9548) coordinates. The local time in Hyattsville is 03:05 (01.03.2025)
Drobeta-Turnu Severin is located in Mehedinţi, Romania within 44° 37' 59.88" N 22° 38' 60" E (44.6333, 22.6500) coordinates. The local time in Drobeta-Turnu Severin is 10:05 (01.03.2025)
The calculated flying distance from Drobeta-Turnu Severin to Drobeta-Turnu Severin is 4,805.20 miles which is equal to 7,733.22 km.
Hyattsville, Maryland, United States
Related Distances from Hyattsville
Drobeta-Turnu Severin, Mehedinţi, Romania