Distance from Isabela to Aleksandrow Lodzki
The shortest distance (air line) between Isabela and Aleksandrow Lodzki is 5,066.13 mi (8,153.15 km).
How far is Isabela from Aleksandrow Lodzki
Isabela is located in Puerto Rico, United States within 18° 29' 56.76" N -68° 58' 40.8" W (18.4991, -67.0220) coordinates. The local time in Isabela is 21:19 (06.06.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 02:19 (07.06.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 5,066.13 miles which is equal to 8,153.15 km.
Isabela, Puerto Rico, United States
Related Distances from Isabela
Aleksandrow Lodzki, Łódzki, Poland