Distance from Jacksonville to Begijnendijk
The shortest distance (air line) between Jacksonville and Begijnendijk is 4,475.85 mi (7,203.19 km).
How far is Jacksonville from Begijnendijk
Jacksonville is located in Florida, United States within 30° 19' 55.92" N -82° 19' 30.36" W (30.3322, -81.6749) coordinates. The local time in Jacksonville is 16:45 (16.11.2024)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 22:45 (16.11.2024)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,475.85 miles which is equal to 7,203.19 km.
Jacksonville, Florida, United States
Related Distances from Jacksonville
Begijnendijk, Arr. Leuven, Belgium