Distance from Jacksonville Beach to Begijnendijk
The shortest distance (air line) between Jacksonville Beach and Begijnendijk is 4,467.34 mi (7,189.49 km).
How far is Jacksonville Beach from Begijnendijk
Jacksonville Beach is located in Florida, United States within 30° 16' 41.52" N -82° 35' 43.8" W (30.2782, -81.4045) coordinates. The local time in Jacksonville Beach is 16:47 (16.11.2024)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 22:47 (16.11.2024)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,467.34 miles which is equal to 7,189.49 km.
Jacksonville Beach, Florida, United States
Related Distances from Jacksonville Beach
Begijnendijk, Arr. Leuven, Belgium