Distance from Jacksonville Beach to Cesky Tesin
The shortest distance (air line) between Jacksonville Beach and Cesky Tesin is 5,063.53 mi (8,148.96 km).
How far is Jacksonville Beach from Cesky Tesin
Jacksonville Beach is located in Florida, United States within 30° 16' 41.52" N -82° 35' 43.8" W (30.2782, -81.4045) coordinates. The local time in Jacksonville Beach is 11:39 (17.11.2024)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 17:39 (17.11.2024)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 5,063.53 miles which is equal to 8,148.96 km.
Jacksonville Beach, Florida, United States
Related Distances from Jacksonville Beach
Cesky Tesin, Moravskoslezský kraj, Czechia