Distance from Jacksonville Beach to Lyaskovets
The shortest distance (air line) between Jacksonville Beach and Lyaskovets is 5,586.78 mi (8,991.05 km).
How far is Jacksonville Beach from Lyaskovets
Jacksonville Beach is located in Florida, United States within 30° 16' 41.52" N -82° 35' 43.8" W (30.2782, -81.4045) coordinates. The local time in Jacksonville Beach is 06:23 (17.11.2024)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 13:23 (17.11.2024)
The calculated flying distance from Lyaskovets to Lyaskovets is 5,586.78 miles which is equal to 8,991.05 km.
Jacksonville Beach, Florida, United States
Related Distances from Jacksonville Beach
Lyaskovets, Veliko Tarnovo, Bulgaria