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      Distance from Jacksonville Beach to Sint-Martens-Lennik

      The shortest distance (air line) between Jacksonville Beach and Sint-Martens-Lennik is 4,445.45 mi (7,154.26 km).

      How far is Jacksonville Beach from Sint-Martens-Lennik

      Jacksonville Beach is located in Florida, United States within 30° 16' 41.52" N -82° 35' 43.8" W (30.2782, -81.4045) coordinates. The local time in Jacksonville Beach is 01:17 (17.11.2024)

      Sint-Martens-Lennik is located in Arr. Halle-Vilvoorde, Belgium within 50° 47' 60" N 4° 9' 0" E (50.8000, 4.1500) coordinates. The local time in Sint-Martens-Lennik is 07:17 (17.11.2024)

      The calculated flying distance from Sint-Martens-Lennik to Sint-Martens-Lennik is 4,445.45 miles which is equal to 7,154.26 km.

      Jacksonville Beach, Florida, United States

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      Sint-Martens-Lennik, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Martens-Lennik