Distance from Jacksonville Beach to Slavonski Brod
The shortest distance (air line) between Jacksonville Beach and Slavonski Brod is 5,185.80 mi (8,345.73 km).
How far is Jacksonville Beach from Slavonski Brod
Jacksonville Beach is located in Florida, United States within 30° 16' 41.52" N -82° 35' 43.8" W (30.2782, -81.4045) coordinates. The local time in Jacksonville Beach is 09:48 (17.11.2024)
Slavonski Brod is located in Brodsko-posavska županija, Croatia within 45° 10' 0.12" N 18° 1' 0.12" E (45.1667, 18.0167) coordinates. The local time in Slavonski Brod is 15:48 (17.11.2024)
The calculated flying distance from Slavonski Brod to Slavonski Brod is 5,185.80 miles which is equal to 8,345.73 km.
Jacksonville Beach, Florida, United States
Related Distances from Jacksonville Beach
Slavonski Brod, Brodsko-posavska županija, Croatia