Distance from Jacksonville Beach to Sveti Ivan Zelina
The shortest distance (air line) between Jacksonville Beach and Sveti Ivan Zelina is 5,084.40 mi (8,182.56 km).
How far is Jacksonville Beach from Sveti Ivan Zelina
Jacksonville Beach is located in Florida, United States within 30° 16' 41.52" N -82° 35' 43.8" W (30.2782, -81.4045) coordinates. The local time in Jacksonville Beach is 09:27 (17.11.2024)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 15:27 (17.11.2024)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,084.40 miles which is equal to 8,182.56 km.
Jacksonville Beach, Florida, United States
Related Distances from Jacksonville Beach
Sveti Ivan Zelina, Zagrebačka županija, Croatia