Distance from James Island to Asenovgrad
The shortest distance (air line) between James Island and Asenovgrad is 5,412.18 mi (8,710.06 km).
How far is James Island from Asenovgrad
James Island is located in South Carolina, United States within 32° 44' 7.08" N -80° 3' 38.16" W (32.7353, -79.9394) coordinates. The local time in James Island is 09:41 (04.11.2025)
Asenovgrad is located in Plovdiv, Bulgaria within 42° 1' 0.12" N 24° 52' 0.12" E (42.0167, 24.8667) coordinates. The local time in Asenovgrad is 16:41 (04.11.2025)
The calculated flying distance from Asenovgrad to Asenovgrad is 5,412.18 miles which is equal to 8,710.06 km.
James Island, South Carolina, United States