Distance from Jamestown to Celakovice
The shortest distance (air line) between Jamestown and Celakovice is 4,228.71 mi (6,805.45 km).
How far is Jamestown from Celakovice
Jamestown is located in New York, United States within 42° 5' 51.36" N -80° 45' 47.88" W (42.0976, -79.2367) coordinates. The local time in Jamestown is 11:24 (17.11.2024)
Celakovice is located in Středočeský kraj, Czechia within 50° 9' 38.16" N 14° 45' 0" E (50.1606, 14.7500) coordinates. The local time in Celakovice is 17:24 (17.11.2024)
The calculated flying distance from Celakovice to Celakovice is 4,228.71 miles which is equal to 6,805.45 km.
Jamestown, New York, United States
Related Distances from Jamestown
Celakovice, Středočeský kraj, Czechia